Base | Representation |
---|---|
bin | 10011010000000000001100… |
… | …00110110111110011110011 |
3 | 12112212211111002102110010202 |
4 | 21220000012012313303303 |
5 | 21022024000313243011 |
6 | 230010421504545415 |
7 | 11626223036162501 |
oct | 1150000606676363 |
9 | 175784432373122 |
10 | 42331300134131 |
11 | 125406703951a8 |
12 | 48b810a92226b |
13 | 1a80a944a6858 |
14 | a64bbb06d671 |
15 | 4d62031ec23b |
hex | 2680061b7cf3 |
42331300134131 has 2 divisors, whose sum is σ = 42331300134132. Its totient is φ = 42331300134130.
The previous prime is 42331300134127. The next prime is 42331300134191. The reversal of 42331300134131 is 13143100313324.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42331300134131 - 22 = 42331300134127 is a prime.
It is a super-2 number, since 2×423313001341312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 42331300134094 and 42331300134103.
It is not a weakly prime, because it can be changed into another prime (42331300134191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21165650067065 + 21165650067066.
It is an arithmetic number, because the mean of its divisors is an integer number (21165650067066).
Almost surely, 242331300134131 is an apocalyptic number.
42331300134131 is a deficient number, since it is larger than the sum of its proper divisors (1).
42331300134131 is an equidigital number, since it uses as much as digits as its factorization.
42331300134131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 42331300134131 its reverse (13143100313324), we get a palindrome (55474400447455).
The spelling of 42331300134131 in words is "forty-two trillion, three hundred thirty-one billion, three hundred million, one hundred thirty-four thousand, one hundred thirty-one".
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