Base | Representation |
---|---|
bin | 111101100110011010001… |
… | …101011111011001101001 |
3 | 112222200110002221111020201 |
4 | 331212122031133121221 |
5 | 1023323422240424223 |
6 | 13000401215152201 |
7 | 614555623302124 |
oct | 75463215373151 |
9 | 15880402844221 |
10 | 4233130014313 |
11 | 1392295598992 |
12 | 5844aa815661 |
13 | 24924aab6375 |
14 | 108c554373bb |
15 | 751a7c2eead |
hex | 3d99a35f669 |
4233130014313 has 2 divisors, whose sum is σ = 4233130014314. Its totient is φ = 4233130014312.
The previous prime is 4233130014247. The next prime is 4233130014329. The reversal of 4233130014313 is 3134100313324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3550330229824 + 682799784489 = 1884232^2 + 826317^2 .
It is a cyclic number.
It is not a de Polignac number, because 4233130014313 - 213 = 4233130006121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4233130012313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565007156 + 2116565007157.
It is an arithmetic number, because the mean of its divisors is an integer number (2116565007157).
Almost surely, 24233130014313 is an apocalyptic number.
It is an amenable number.
4233130014313 is a deficient number, since it is larger than the sum of its proper divisors (1).
4233130014313 is an equidigital number, since it uses as much as digits as its factorization.
4233130014313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 4233130014313 its reverse (3134100313324), we get a palindrome (7367230327637).
The spelling of 4233130014313 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, fourteen thousand, three hundred thirteen".
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