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4233130323953 is a prime number
BaseRepresentation
bin111101100110011010001…
…110101010111111110001
3112222200110010112012222212
4331212122032222333301
51023323422330331303
613000401225541505
7614555626031636
oct75463216527761
915880403465885
104233130323953
11139229578a593
125844aa944895
1324924ab9429b
14108c554b818d
15751a7c91ad8
hex3d99a3aaff1

4233130323953 has 2 divisors, whose sum is σ = 4233130323954. Its totient is φ = 4233130323952.

The previous prime is 4233130323949. The next prime is 4233130324043. The reversal of 4233130323953 is 3593230313324.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4220095078369 + 13035245584 = 2054287^2 + 114172^2 .

It is a cyclic number.

It is not a de Polignac number, because 4233130323953 - 22 = 4233130323949 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 4233130323953.

It is not a weakly prime, because it can be changed into another prime (4233130323913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565161976 + 2116565161977.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565161977).

Almost surely, 24233130323953 is an apocalyptic number.

It is an amenable number.

4233130323953 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233130323953 is an equidigital number, since it uses as much as digits as its factorization.

4233130323953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 524880, while the sum is 41.

The spelling of 4233130323953 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, three hundred twenty-three thousand, nine hundred fifty-three".