Base | Representation |
---|---|
bin | 111101100110011010001… |
… | …110111111111111110011 |
3 | 112222200110010200120222201 |
4 | 331212122032333333303 |
5 | 1023323422341104341 |
6 | 13000401231444031 |
7 | 614555626540501 |
oct | 75463216777763 |
9 | 15880403616881 |
10 | 4233130409971 |
11 | 1392295839181 |
12 | 5844aa986617 |
13 | 24924abc4498 |
14 | 108c554db671 |
15 | 751a7cac331 |
hex | 3d99a3bfff3 |
4233130409971 has 2 divisors, whose sum is σ = 4233130409972. Its totient is φ = 4233130409970.
The previous prime is 4233130409927. The next prime is 4233130410013. The reversal of 4233130409971 is 1799040313324.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4233130409971 - 211 = 4233130407923 is a prime.
It is not a weakly prime, because it can be changed into another prime (4233130409171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565204985 + 2116565204986.
It is an arithmetic number, because the mean of its divisors is an integer number (2116565204986).
Almost surely, 24233130409971 is an apocalyptic number.
4233130409971 is a deficient number, since it is larger than the sum of its proper divisors (1).
4233130409971 is an equidigital number, since it uses as much as digits as its factorization.
4233130409971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 489888, while the sum is 46.
The spelling of 4233130409971 in words is "four trillion, two hundred thirty-three billion, one hundred thirty million, four hundred nine thousand, nine hundred seventy-one".
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