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4233131121113 is a prime number
BaseRepresentation
bin111101100110011010010…
…001101101100111011001
3112222200110012000201111022
4331212122101231213121
51023323423031333423
613000401255012225
7614555635562006
oct75463221554731
915880405021438
104233131121113
1113922961844a4
125844ab06a075
1324924b0b308b
14108c556448ad
15751a7d9cdc8
hex3d99a46d9d9

4233131121113 has 2 divisors, whose sum is σ = 4233131121114. Its totient is φ = 4233131121112.

The previous prime is 4233131121061. The next prime is 4233131121157. The reversal of 4233131121113 is 3111211313324.

4233131121113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2786121812224 + 1447009308889 = 1669168^2 + 1202917^2 .

It is a cyclic number.

It is not a de Polignac number, because 4233131121113 - 228 = 4232862685657 is a prime.

It is not a weakly prime, because it can be changed into another prime (4233131129113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116565560556 + 2116565560557.

It is an arithmetic number, because the mean of its divisors is an integer number (2116565560557).

Almost surely, 24233131121113 is an apocalyptic number.

It is an amenable number.

4233131121113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233131121113 is an equidigital number, since it uses as much as digits as its factorization.

4233131121113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 26.

Adding to 4233131121113 its reverse (3111211313324), we get a palindrome (7344342434437).

The spelling of 4233131121113 in words is "four trillion, two hundred thirty-three billion, one hundred thirty-one million, one hundred twenty-one thousand, one hundred thirteen".