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42331314313402 = 221165657156701
BaseRepresentation
bin10011010000000000001101…
…11100111101100010111010
312112212211112002002211102221
421220000012330331202322
521022024012431012102
6230010423132514254
711626223300536462
oct1150000674754272
9175784462084387
1042331314313402
111254067839a304
1248b811361b98a
131a80a973cc75a
14a64bbccc0ba2
154d620459d637
hex268006f3d8ba

42331314313402 has 4 divisors (see below), whose sum is σ = 63496971470106. Its totient is φ = 21165657156700.

The previous prime is 42331314313399. The next prime is 42331314313429. The reversal of 42331314313402 is 20431341313324.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 42242057373321 + 89256940081 = 6499389^2 + 298759^2 .

It is a super-3 number, since 3×423313143134023 (a number of 42 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10582828578349 + ... + 10582828578352.

Almost surely, 242331314313402 is an apocalyptic number.

42331314313402 is a deficient number, since it is larger than the sum of its proper divisors (21165657156704).

42331314313402 is a wasteful number, since it uses less digits than its factorization.

42331314313402 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21165657156703.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 42331314313402 its reverse (20431341313324), we get a palindrome (62762655626726).

The spelling of 42331314313402 in words is "forty-two trillion, three hundred thirty-one billion, three hundred fourteen million, three hundred thirteen thousand, four hundred two".

Divisors: 1 2 21165657156701 42331314313402