Base | Representation |
---|---|
bin | 111101100110011010111… |
… | …000001101100011011011 |
3 | 112222200110220000110111211 |
4 | 331212122320031203123 |
5 | 1023323433122312103 |
6 | 13000402255203551 |
7 | 614556120424414 |
oct | 75463270154333 |
9 | 15880426013454 |
10 | 4233141213403 |
11 | 13922a0947a33 |
12 | 5844b25165b7 |
13 | 24925020794b |
14 | 108c56b1080b |
15 | 751a8be336d |
hex | 3d99ae0d8db |
4233141213403 has 2 divisors, whose sum is σ = 4233141213404. Its totient is φ = 4233141213402.
The previous prime is 4233141213383. The next prime is 4233141213437. The reversal of 4233141213403 is 3043121413324.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4233141213403 - 213 = 4233141205211 is a prime.
It is a super-2 number, since 2×42331412134032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4233141213443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116570606701 + 2116570606702.
It is an arithmetic number, because the mean of its divisors is an integer number (2116570606702).
Almost surely, 24233141213403 is an apocalyptic number.
4233141213403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4233141213403 is an equidigital number, since it uses as much as digits as its factorization.
4233141213403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 4233141213403 its reverse (3043121413324), we get a palindrome (7276262626727).
The spelling of 4233141213403 in words is "four trillion, two hundred thirty-three billion, one hundred forty-one million, two hundred thirteen thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •