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4233142401353 is a prime number
BaseRepresentation
bin111101100110011010111…
…100101111100101001001
3112222200110222020211001222
4331212122330233211021
51023323433423320403
613000402340451425
7614556133503005
oct75463274574511
915880428224058
104233142401353
1113922a1589508
125844b29a9b75
13249250532588
14108c56d3d705
15751a8d7a338
hex3d99af2f949

4233142401353 has 2 divisors, whose sum is σ = 4233142401354. Its totient is φ = 4233142401352.

The previous prime is 4233142401317. The next prime is 4233142401377. The reversal of 4233142401353 is 3531042413324.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2939743426624 + 1293398974729 = 1714568^2 + 1137277^2 .

It is a cyclic number.

It is not a de Polignac number, because 4233142401353 - 28 = 4233142401097 is a prime.

It is a super-3 number, since 3×42331424013533 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (4233142407353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116571200676 + 2116571200677.

It is an arithmetic number, because the mean of its divisors is an integer number (2116571200677).

Almost surely, 24233142401353 is an apocalyptic number.

It is an amenable number.

4233142401353 is a deficient number, since it is larger than the sum of its proper divisors (1).

4233142401353 is an equidigital number, since it uses as much as digits as its factorization.

4233142401353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 4233142401353 its reverse (3531042413324), we get a palindrome (7764184814677).

The spelling of 4233142401353 in words is "four trillion, two hundred thirty-three billion, one hundred forty-two million, four hundred one thousand, three hundred fifty-three".