Base | Representation |
---|---|
bin | 10011010000000000011011… |
… | …11110010101100001000001 |
3 | 12112212211211021202201210222 |
4 | 21220000031332111201001 |
5 | 21022024233110123431 |
6 | 230010442541432425 |
7 | 11626226231041244 |
oct | 1150001576254101 |
9 | 175784737681728 |
10 | 42331432114241 |
11 | 12540728939876 |
12 | 48b8146b6b715 |
13 | 1a80ab59366aa |
14 | a64bd07c725b |
15 | 4d620eabc57b |
hex | 26800df95841 |
42331432114241 has 2 divisors, whose sum is σ = 42331432114242. Its totient is φ = 42331432114240.
The previous prime is 42331432114193. The next prime is 42331432114249. The reversal of 42331432114241 is 14241123413324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41621903862016 + 709528252225 = 6451504^2 + 842335^2 .
It is a cyclic number.
It is not a de Polignac number, because 42331432114241 - 230 = 42330358372417 is a prime.
It is not a weakly prime, because it can be changed into another prime (42331432114249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21165716057120 + 21165716057121.
It is an arithmetic number, because the mean of its divisors is an integer number (21165716057121).
Almost surely, 242331432114241 is an apocalyptic number.
It is an amenable number.
42331432114241 is a deficient number, since it is larger than the sum of its proper divisors (1).
42331432114241 is an equidigital number, since it uses as much as digits as its factorization.
42331432114241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 35.
Adding to 42331432114241 its reverse (14241123413324), we get a palindrome (56572555527565).
The spelling of 42331432114241 in words is "forty-two trillion, three hundred thirty-one billion, four hundred thirty-two million, one hundred fourteen thousand, two hundred forty-one".
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