Base | Representation |
---|---|
bin | 111101100111101000010… |
… | …110111101110110000001 |
3 | 112222210211111000121201022 |
4 | 331213220112331312001 |
5 | 1023334113411334103 |
6 | 13001135252515225 |
7 | 614633253442055 |
oct | 75475026756601 |
9 | 15883744017638 |
10 | 4234441121153 |
11 | 13928a8691961 |
12 | 5847b591bb15 |
13 | 2493c960c929 |
14 | 108d3b609c65 |
15 | 75232db6138 |
hex | 3d9e85bdd81 |
4234441121153 has 2 divisors, whose sum is σ = 4234441121154. Its totient is φ = 4234441121152.
The previous prime is 4234441121111. The next prime is 4234441121203. The reversal of 4234441121153 is 3511211444324.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4207142481424 + 27298639729 = 2051132^2 + 165223^2 .
It is a cyclic number.
It is not a de Polignac number, because 4234441121153 - 26 = 4234441121089 is a prime.
It is a super-2 number, since 2×42344411211532 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4234441120153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2117220560576 + 2117220560577.
It is an arithmetic number, because the mean of its divisors is an integer number (2117220560577).
Almost surely, 24234441121153 is an apocalyptic number.
It is an amenable number.
4234441121153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4234441121153 is an equidigital number, since it uses as much as digits as its factorization.
4234441121153 is an evil number, because the sum of its binary digits is even.
The product of its digits is 46080, while the sum is 35.
Adding to 4234441121153 its reverse (3511211444324), we get a palindrome (7745652565477).
The spelling of 4234441121153 in words is "four trillion, two hundred thirty-four billion, four hundred forty-one million, one hundred twenty-one thousand, one hundred fifty-three".
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