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4241104043401 is a prime number
BaseRepresentation
bin111101101101110101011…
…111111111110110001001
3120000110000211111010202101
4331231311133333312021
51023441240113342101
613004200350233401
7615260340364261
oct75556537776611
916013024433671
104241104043401
111395707737a75
12585b551b5861
13249c1bb35384
141093b04a07a1
15754c2cea401
hex3db757ffd89

4241104043401 has 2 divisors, whose sum is σ = 4241104043402. Its totient is φ = 4241104043400.

The previous prime is 4241104043389. The next prime is 4241104043419. The reversal of 4241104043401 is 1043404011424.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4174764314176 + 66339729225 = 2043224^2 + 257565^2 .

It is a cyclic number.

It is not a de Polignac number, because 4241104043401 - 27 = 4241104043273 is a prime.

It is a super-2 number, since 2×42411040434012 (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4241104043401.

It is not a weakly prime, because it can be changed into another prime (4241104043461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2120552021700 + 2120552021701.

It is an arithmetic number, because the mean of its divisors is an integer number (2120552021701).

Almost surely, 24241104043401 is an apocalyptic number.

It is an amenable number.

4241104043401 is a deficient number, since it is larger than the sum of its proper divisors (1).

4241104043401 is an equidigital number, since it uses as much as digits as its factorization.

4241104043401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 4241104043401 its reverse (1043404011424), we get a palindrome (5284508054825).

The spelling of 4241104043401 in words is "four trillion, two hundred forty-one billion, one hundred four million, forty-three thousand, four hundred one".