Base | Representation |
---|---|
bin | 111101101111100110101… |
… | …101100000100000000001 |
3 | 120000121221012110222111111 |
4 | 331233212231200200001 |
5 | 1024004132333113213 |
6 | 13005113040243321 |
7 | 615355402626424 |
oct | 75574655404001 |
9 | 16017835428444 |
10 | 4243003410433 |
11 | 13964a18a0597 |
12 | 5863a5310541 |
13 | 24a1624a6aa8 |
14 | 1095108419bb |
15 | 75584930a3d |
hex | 3dbe6b60801 |
4243003410433 has 2 divisors, whose sum is σ = 4243003410434. Its totient is φ = 4243003410432.
The previous prime is 4243003410367. The next prime is 4243003410461. The reversal of 4243003410433 is 3340143003424.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2492536815729 + 1750466594704 = 1578777^2 + 1323052^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4243003410433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4243003410395 and 4243003410404.
It is not a weakly prime, because it can be changed into another prime (4243003410493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2121501705216 + 2121501705217.
It is an arithmetic number, because the mean of its divisors is an integer number (2121501705217).
Almost surely, 24243003410433 is an apocalyptic number.
It is an amenable number.
4243003410433 is a deficient number, since it is larger than the sum of its proper divisors (1).
4243003410433 is an equidigital number, since it uses as much as digits as its factorization.
4243003410433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 31.
Adding to 4243003410433 its reverse (3340143003424), we get a palindrome (7583146413857).
The spelling of 4243003410433 in words is "four trillion, two hundred forty-three billion, three million, four hundred ten thousand, four hundred thirty-three".
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