Base | Representation |
---|---|
bin | 111101110000101110110… |
… | …101000001101101001011 |
3 | 120000202001112011211012211 |
4 | 331300232311001231023 |
5 | 1024014122103403003 |
6 | 13005433101245551 |
7 | 615430364104666 |
oct | 75605665015513 |
9 | 16022045154184 |
10 | 4244213341003 |
11 | 1396a6286a309 |
12 | 5866825638b7 |
13 | 24a2c606733c |
14 | 1095c73d86dd |
15 | 75605c7d96d |
hex | 3dc2ed41b4b |
4244213341003 has 2 divisors, whose sum is σ = 4244213341004. Its totient is φ = 4244213341002.
The previous prime is 4244213340989. The next prime is 4244213341097. The reversal of 4244213341003 is 3001433124424.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4244213341003 - 29 = 4244213340491 is a prime.
It is a super-2 number, since 2×42442133410032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4244213341103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2122106670501 + 2122106670502.
It is an arithmetic number, because the mean of its divisors is an integer number (2122106670502).
Almost surely, 24244213341003 is an apocalyptic number.
4244213341003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4244213341003 is an equidigital number, since it uses as much as digits as its factorization.
4244213341003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 4244213341003 its reverse (3001433124424), we get a palindrome (7245646465427).
The spelling of 4244213341003 in words is "four trillion, two hundred forty-four billion, two hundred thirteen million, three hundred forty-one thousand, three".
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