Base | Representation |
---|---|
bin | 1010001001000… |
… | …0010011110011 |
3 | 2222000221212012 |
4 | 2202100103303 |
5 | 41342043011 |
6 | 4115353135 |
7 | 1024351133 |
oct | 242202363 |
9 | 88027765 |
10 | 42534131 |
11 | 22011582 |
12 | 122b27ab |
13 | 8a73133 |
14 | 5912ac3 |
15 | 3b02a8b |
hex | 28904f3 |
42534131 has 2 divisors, whose sum is σ = 42534132. Its totient is φ = 42534130.
The previous prime is 42534091. The next prime is 42534157. The reversal of 42534131 is 13143524.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 42534131 - 26 = 42534067 is a prime.
It is a super-2 number, since 2×425341312 = 3618304599850322, which contains 22 as substring.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 42534097 and 42534106.
It is not a weakly prime, because it can be changed into another prime (42534161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21267065 + 21267066.
It is an arithmetic number, because the mean of its divisors is an integer number (21267066).
Almost surely, 242534131 is an apocalyptic number.
42534131 is a deficient number, since it is larger than the sum of its proper divisors (1).
42534131 is an equidigital number, since it uses as much as digits as its factorization.
42534131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1440, while the sum is 23.
The square root of 42534131 is about 6521.8196080542. The cubic root of 42534131 is about 349.0699963325.
Adding to 42534131 its reverse (13143524), we get a palindrome (55677655).
The spelling of 42534131 in words is "forty-two million, five hundred thirty-four thousand, one hundred thirty-one".
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