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42652055354371 is a prime number
BaseRepresentation
bin10011011001010101101001…
…00110111011110000000011
312121000111102001221220112121
421230222310212323300003
521042302402132314441
6230414030030305111
711661336456442261
oct1154526446736003
9177014361856477
1042652055354371
11126546a9346681
12494a307058197
131aa50c12b4968
14a765288c7431
154de727aa5dd1
hex26cab49bbc03

42652055354371 has 2 divisors, whose sum is σ = 42652055354372. Its totient is φ = 42652055354370.

The previous prime is 42652055354173. The next prime is 42652055354399. The reversal of 42652055354371 is 17345355025624.

42652055354371 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (42652055354173) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 42652055354371 - 211 = 42652055352323 is a prime.

It is not a weakly prime, because it can be changed into another prime (42652055354771) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21326027677185 + 21326027677186.

It is an arithmetic number, because the mean of its divisors is an integer number (21326027677186).

Almost surely, 242652055354371 is an apocalyptic number.

42652055354371 is a deficient number, since it is larger than the sum of its proper divisors (1).

42652055354371 is an equidigital number, since it uses as much as digits as its factorization.

42652055354371 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120000, while the sum is 52.

The spelling of 42652055354371 in words is "forty-two trillion, six hundred fifty-two billion, fifty-five million, three hundred fifty-four thousand, three hundred seventy-one".