Base | Representation |
---|---|
bin | 10011011010000000011010… |
… | …00000011101111110100001 |
3 | 12121002200200001100100110102 |
4 | 21231000031000131332201 |
5 | 21043141411344422044 |
6 | 230432344102312145 |
7 | 11663111416543112 |
oct | 1155001500357641 |
9 | 177080601310412 |
10 | 42675013279649 |
11 | 1266340a508743 |
12 | 4952853728655 |
13 | 1aa730c731b2a |
14 | a776a5982209 |
15 | 4e011d35424e |
hex | 26d00d01dfa1 |
42675013279649 has 2 divisors, whose sum is σ = 42675013279650. Its totient is φ = 42675013279648.
The previous prime is 42675013279607. The next prime is 42675013279721. The reversal of 42675013279649 is 94697231057624.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38341359361600 + 4333653918049 = 6192040^2 + 2081743^2 .
It is a cyclic number.
It is not a de Polignac number, because 42675013279649 - 212 = 42675013275553 is a prime.
It is not a weakly prime, because it can be changed into another prime (42675013279049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21337506639824 + 21337506639825.
It is an arithmetic number, because the mean of its divisors is an integer number (21337506639825).
Almost surely, 242675013279649 is an apocalyptic number.
It is an amenable number.
42675013279649 is a deficient number, since it is larger than the sum of its proper divisors (1).
42675013279649 is an equidigital number, since it uses as much as digits as its factorization.
42675013279649 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 137168640, while the sum is 65.
The spelling of 42675013279649 in words is "forty-two trillion, six hundred seventy-five billion, thirteen million, two hundred seventy-nine thousand, six hundred forty-nine".
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