Base | Representation |
---|---|
bin | 1100011011000011110… |
… | …01100101011111001011 |
3 | 1111210202111202110110122 |
4 | 12031201321211133023 |
5 | 23443134111414021 |
6 | 524031201333455 |
7 | 42560412146516 |
oct | 6154171453713 |
9 | 1453674673418 |
10 | 426844248011 |
11 | 1550294a5235 |
12 | 6a88533728b |
13 | 31335c87b6c |
14 | 1693345dd7d |
15 | b183464bab |
hex | 6361e657cb |
426844248011 has 2 divisors, whose sum is σ = 426844248012. Its totient is φ = 426844248010.
The previous prime is 426844247971. The next prime is 426844248023. The reversal of 426844248011 is 110842448624.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 426844248011 - 238 = 151966341067 is a prime.
It is a super-3 number, since 3×4268442480113 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (426844248031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 213422124005 + 213422124006.
It is an arithmetic number, because the mean of its divisors is an integer number (213422124006).
Almost surely, 2426844248011 is an apocalyptic number.
426844248011 is a deficient number, since it is larger than the sum of its proper divisors (1).
426844248011 is an equidigital number, since it uses as much as digits as its factorization.
426844248011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 393216, while the sum is 44.
The spelling of 426844248011 in words is "four hundred twenty-six billion, eight hundred forty-four million, two hundred forty-eight thousand, eleven".
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