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42811115685313 is a prime number
BaseRepresentation
bin10011011101111101111010…
…10101111100010111000001
312121120200222021000220220211
421232332331111330113001
521102404131103412223
6231015053253234121
712006000233110453
oct1156767525742701
9177520867026824
1042811115685313
11127061017a2538
1249750b8032941
131ab70bc978b91
14a800d76b62d3
154e3936cccd0d
hex26efbd57c5c1

42811115685313 has 2 divisors, whose sum is σ = 42811115685314. Its totient is φ = 42811115685312.

The previous prime is 42811115685251. The next prime is 42811115685389. The reversal of 42811115685313 is 31358651111824.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 32719864336384 + 10091251348929 = 5720128^2 + 3176673^2 .

It is a cyclic number.

It is not a de Polignac number, because 42811115685313 - 221 = 42811113588161 is a prime.

It is not a weakly prime, because it can be changed into another prime (42811115685113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21405557842656 + 21405557842657.

It is an arithmetic number, because the mean of its divisors is an integer number (21405557842657).

Almost surely, 242811115685313 is an apocalyptic number.

It is an amenable number.

42811115685313 is a deficient number, since it is larger than the sum of its proper divisors (1).

42811115685313 is an equidigital number, since it uses as much as digits as its factorization.

42811115685313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 691200, while the sum is 49.

The spelling of 42811115685313 in words is "forty-two trillion, eight hundred eleven billion, one hundred fifteen million, six hundred eighty-five thousand, three hundred thirteen".