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42811266498 = 2371113172291831
BaseRepresentation
bin100111110111110000…
…000001010111000010
311002111120221200010220
4213313300001113002
51200134141011443
631400042003510
73043621522020
oct476760012702
9132446850126
1042811266498
1117179931190
1283694a6596
134063625970
142101ac5710
1511a86e9a83
hex9f7c015c2

42811266498 has 256 divisors, whose sum is σ = 122322493440. Its totient is φ = 9613209600.

The previous prime is 42811266479. The next prime is 42811266529. The reversal of 42811266498 is 89466211824.

It is a Harshad number since it is a multiple of its sum of digits (51).

It is a self number, because there is not a number n which added to its sum of digits gives 42811266498.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 23380443 + ... + 23382273.

It is an arithmetic number, because the mean of its divisors is an integer number (477822240).

Almost surely, 242811266498 is an apocalyptic number.

It is a practical number, because each smaller number is the sum of distinct divisors of 42811266498, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (61161246720).

42811266498 is an abundant number, since it is smaller than the sum of its proper divisors (79511226942).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

42811266498 is a wasteful number, since it uses less digits than its factorization.

42811266498 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2113.

The product of its digits is 1327104, while the sum is 51.

The spelling of 42811266498 in words is "forty-two billion, eight hundred eleven million, two hundred sixty-six thousand, four hundred ninety-eight".