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43000131131143 = 282891520030087
BaseRepresentation
bin10011100011011101111111…
…00010101001011100000111
312122020202212001221102212121
421301232333202221130013
521114003232032144033
6231241553150230411
712025441222642264
oct1161567742513407
9178222761842777
1043000131131143
111277928701559a
1249a5868ab5407
131acbb8331ac54
14a8930898826b
154e87eac1462d
hex271bbf8a9707

43000131131143 has 4 divisors (see below), whose sum is σ = 43001651189520. Its totient is φ = 42998611072768.

The previous prime is 43000131131141. The next prime is 43000131131147. The reversal of 43000131131143 is 34113113100034.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43000131131143 - 21 = 43000131131141 is a prime.

It is a super-2 number, since 2×430001311311432 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43000131131141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 759986755 + ... + 760043332.

It is an arithmetic number, because the mean of its divisors is an integer number (10750412797380).

Almost surely, 243000131131143 is an apocalyptic number.

43000131131143 is a deficient number, since it is larger than the sum of its proper divisors (1520058377).

43000131131143 is a wasteful number, since it uses less digits than its factorization.

43000131131143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1520058376.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 43000131131143 its reverse (34113113100034), we get a palindrome (77113244231177).

The spelling of 43000131131143 in words is "forty-three trillion, one hundred thirty-one million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 28289 1520030087 43000131131143