Base | Representation |
---|---|
bin | 111110100100101101001… |
… | …111111010111001011111 |
3 | 120020002002212220112121221 |
4 | 332210231033322321133 |
5 | 1030422420440131143 |
6 | 13051222542034211 |
7 | 622444352633443 |
oct | 76445517727137 |
9 | 16202085815557 |
10 | 4300021411423 |
11 | 14086a0a92661 |
12 | 595458578967 |
13 | 25264b1b300a |
14 | 10c19d256823 |
15 | 76cc04982ed |
hex | 3e92d3fae5f |
4300021411423 has 4 divisors (see below), whose sum is σ = 4300027169488. Its totient is φ = 4300015653360.
The previous prime is 4300021411351. The next prime is 4300021411471. The reversal of 4300021411423 is 3241141200034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4300021411423 - 221 = 4300019314271 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4300021411823) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1556283 + ... + 3319948.
It is an arithmetic number, because the mean of its divisors is an integer number (1075006792372).
Almost surely, 24300021411423 is an apocalyptic number.
4300021411423 is a deficient number, since it is larger than the sum of its proper divisors (5758065).
4300021411423 is an equidigital number, since it uses as much as digits as its factorization.
4300021411423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5758064.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4300021411423 its reverse (3241141200034), we get a palindrome (7541162611457).
The spelling of 4300021411423 in words is "four trillion, three hundred billion, twenty-one million, four hundred eleven thousand, four hundred twenty-three".
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