Base | Representation |
---|---|
bin | 111110100100101110000… |
… | …000000110100100101001 |
3 | 120020002010202200020201202 |
4 | 332210232000012210221 |
5 | 1030422432203322103 |
6 | 13051224112453545 |
7 | 622444565200643 |
oct | 76445600064451 |
9 | 16202122606652 |
10 | 4300034042153 |
11 | 14086a812a283 |
12 | 59546084a2b5 |
13 | 2526509b6115 |
14 | 10c1a0bc3893 |
15 | 76cc1640988 |
hex | 3e92e006929 |
4300034042153 has 2 divisors, whose sum is σ = 4300034042154. Its totient is φ = 4300034042152.
The previous prime is 4300034042131. The next prime is 4300034042191. The reversal of 4300034042153 is 3512404300034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2185926766144 + 2114107276009 = 1478488^2 + 1453997^2 .
It is a cyclic number.
It is not a de Polignac number, because 4300034042153 - 230 = 4298960300329 is a prime.
It is not a weakly prime, because it can be changed into another prime (4300034042653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2150017021076 + 2150017021077.
It is an arithmetic number, because the mean of its divisors is an integer number (2150017021077).
Almost surely, 24300034042153 is an apocalyptic number.
It is an amenable number.
4300034042153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4300034042153 is an equidigital number, since it uses as much as digits as its factorization.
4300034042153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 29.
Adding to 4300034042153 its reverse (3512404300034), we get a palindrome (7812438342187).
The spelling of 4300034042153 in words is "four trillion, three hundred billion, thirty-four million, forty-two thousand, one hundred fifty-three".
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