Base | Representation |
---|---|
bin | 110000111000101100001101… |
… | …1110000000111011100111001 |
3 | 2002101111222111012011222002211 |
4 | 1201301120123300013130321 |
5 | 422330141143320323233 |
6 | 4122313040000455121 |
7 | 156400523004213511 |
oct | 14161303360073471 |
9 | 2071458435158084 |
10 | 430004001339193 |
11 | 115015744636046 |
12 | 402897a601a4a1 |
13 | 155c228495a118 |
14 | 782843a1b6841 |
15 | 34aa5ce3445cd |
hex | 187161bc07739 |
430004001339193 has 2 divisors, whose sum is σ = 430004001339194. Its totient is φ = 430004001339192.
The previous prime is 430004001339179. The next prime is 430004001339229. The reversal of 430004001339193 is 391933100400034.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 216252671403024 + 213751329936169 = 14705532^2 + 14620237^2 .
It is a cyclic number.
It is not a de Polignac number, because 430004001339193 - 241 = 427804978083641 is a prime.
It is not a weakly prime, because it can be changed into another prime (430004001339893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215002000669596 + 215002000669597.
It is an arithmetic number, because the mean of its divisors is an integer number (215002000669597).
Almost surely, 2430004001339193 is an apocalyptic number.
It is an amenable number.
430004001339193 is a deficient number, since it is larger than the sum of its proper divisors (1).
430004001339193 is an equidigital number, since it uses as much as digits as its factorization.
430004001339193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 104976, while the sum is 40.
The spelling of 430004001339193 in words is "four hundred thirty trillion, four billion, one million, three hundred thirty-nine thousand, one hundred ninety-three".
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