Base | Representation |
---|---|
bin | 111110100100110011101… |
… | …110010001111010010101 |
3 | 120020002101110022002211110 |
4 | 332210303232101322111 |
5 | 1030423131242031201 |
6 | 13051241422125233 |
7 | 622450142125344 |
oct | 76446356217225 |
9 | 16202343262743 |
10 | 4300130033301 |
11 | 1408747332903 |
12 | 595488a20819 |
13 | 25266785500b |
14 | 10c1ad84db5b |
15 | 76cc9ca26d6 |
hex | 3e933b91e95 |
4300130033301 has 16 divisors (see below), whose sum is σ = 5761256829120. Its totient is φ = 2852881019520.
The previous prime is 4300130033299. The next prime is 4300130033317. The reversal of 4300130033301 is 1033300310034.
It is not a de Polignac number, because 4300130033301 - 21 = 4300130033299 is a prime.
It is a super-2 number, since 2×43001300333012 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4300130033351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6078985 + ... + 6749393.
It is an arithmetic number, because the mean of its divisors is an integer number (360078551820).
Almost surely, 24300130033301 is an apocalyptic number.
It is an amenable number.
4300130033301 is a deficient number, since it is larger than the sum of its proper divisors (1461126795819).
4300130033301 is a wasteful number, since it uses less digits than its factorization.
4300130033301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680756.
The product of its (nonzero) digits is 972, while the sum is 21.
Adding to 4300130033301 its reverse (1033300310034), we get a palindrome (5333430343335).
The spelling of 4300130033301 in words is "four trillion, three hundred billion, one hundred thirty million, thirty-three thousand, three hundred one".
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