Base | Representation |
---|---|
bin | 1100100001001000001… |
… | …01000000001111111001 |
3 | 1112010011112211111000200 |
4 | 12100210011000033321 |
5 | 24021322104133423 |
6 | 525330334552413 |
7 | 43034220600342 |
oct | 6204405001771 |
9 | 1463145744020 |
10 | 430102021113 |
11 | 1564504183a6 |
12 | 6b434368709 |
13 | 31734ba3b5b |
14 | 16b61da70c9 |
15 | b2c4475d43 |
hex | 64241403f9 |
430102021113 has 24 divisors (see below), whose sum is σ = 675581561928. Its totient is φ = 262574203392.
The previous prime is 430102021103. The next prime is 430102021121. The reversal of 430102021113 is 311120201034.
430102021113 is a `hidden beast` number, since 430 + 1 + 0 + 20 + 211 + 1 + 3 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 154977643584 + 275124377529 = 393672^2 + 524523^2 .
It is not a de Polignac number, because 430102021113 - 212 = 430102017017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (430102021103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 37982506 + ... + 37993827.
It is an arithmetic number, because the mean of its divisors is an integer number (28149231747).
Almost surely, 2430102021113 is an apocalyptic number.
It is an amenable number.
430102021113 is a deficient number, since it is larger than the sum of its proper divisors (245479540815).
430102021113 is a wasteful number, since it uses less digits than its factorization.
430102021113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75976393 (or 75976390 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 430102021113 its reverse (311120201034), we get a palindrome (741222222147).
The spelling of 430102021113 in words is "four hundred thirty billion, one hundred two million, twenty-one thousand, one hundred thirteen".
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