4301100401341 has 4 divisors (see below), whose sum is σ = 4417346358172. Its totient is φ = 4184854444512.

The previous prime is 4301100401309. The next prime is 4301100401431. The reversal of 4301100401341 is 1431040011034.

It is a happy number.

4301100401341 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2464180992441 + 1836919408900 = 1569771^2 + 1355330^2 .

It is not a de Polignac number, because 4301100401341 - 2⁵ = 4301100401309 is a prime.

It is a super-2 number, since 2×4301100401341² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4301100401041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58122978360 + ... + 58122978433.

It is an arithmetic number, because the mean of its divisors is an integer number (1104336589543).

Almost surely, 2^{4301100401341} is an apocalyptic number.

It is an amenable number.

4301100401341 is a deficient number, since it is larger than the sum of its proper divisors (116245956831).

4301100401341 is a wasteful number, since it uses less digits than its factorization.

4301100401341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 116245956830.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4301100401341 its reverse (1431040011034), we get a palindrome (5732140412375).

The spelling of 4301100401341 in words is "four trillion, three hundred one billion, one hundred million, four hundred one thousand, three hundred forty-one".