Base | Representation |
---|---|
bin | 101000000011101010… |
… | …100001010100001001 |
3 | 11010000112001212021210 |
4 | 220003222201110021 |
5 | 1201041323313423 |
6 | 31431542123333 |
7 | 3051566516010 |
oct | 500352412411 |
9 | 133015055253 |
10 | 43011151113 |
11 | 17271745487 |
12 | 8404420549 |
13 | 4095b6c598 |
14 | 2120477a77 |
15 | 11bb02eb93 |
hex | a03aa1509 |
43011151113 has 32 divisors (see below), whose sum is σ = 66260355840. Its totient is φ = 24308305920.
The previous prime is 43011151063. The next prime is 43011151151. The reversal of 43011151113 is 31115111034.
It is not a de Polignac number, because 43011151113 - 210 = 43011150089 is a prime.
It is a super-2 number, since 2×430111511132 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 43011151113.
It is not an unprimeable number, because it can be changed into a prime (43011151163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3499543 + ... + 3511811.
It is an arithmetic number, because the mean of its divisors is an integer number (2070636120).
Almost surely, 243011151113 is an apocalyptic number.
It is an amenable number.
43011151113 is a deficient number, since it is larger than the sum of its proper divisors (23249204727).
43011151113 is a wasteful number, since it uses less digits than its factorization.
43011151113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14097.
The product of its (nonzero) digits is 180, while the sum is 21.
Adding to 43011151113 its reverse (31115111034), we get a palindrome (74126262147).
The spelling of 43011151113 in words is "forty-three billion, eleven million, one hundred fifty-one thousand, one hundred thirteen".
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