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43011320142 = 2371024079051
BaseRepresentation
bin101000000011101011…
…001010100101001110
311010000112101110011010
4220003223022211032
51201041344221032
631431545510050
73051601121550
oct500353124516
9133015343133
1043011320142
111727185047a
1284044a2326
134095bcb4bb
1421204bd4d0
1511bb064ccc
hexa03aca94e

43011320142 has 16 divisors (see below), whose sum is σ = 98311588992. Its totient is φ = 12288948600.

The previous prime is 43011320141. The next prime is 43011320147. The reversal of 43011320142 is 24102311034.

It is a super-2 number, since 2×430113201422 (a number of 22 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43011320141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512039484 + ... + 512039567.

It is an arithmetic number, because the mean of its divisors is an integer number (6144474312).

Almost surely, 243011320142 is an apocalyptic number.

43011320142 is a gapful number since it is divisible by the number (42) formed by its first and last digit.

43011320142 is an abundant number, since it is smaller than the sum of its proper divisors (55300268850).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

43011320142 is a wasteful number, since it uses less digits than its factorization.

43011320142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1024079063.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 43011320142 its reverse (24102311034), we get a palindrome (67113631176).

The spelling of 43011320142 in words is "forty-three billion, eleven million, three hundred twenty thousand, one hundred forty-two".

Divisors: 1 2 3 6 7 14 21 42 1024079051 2048158102 3072237153 6144474306 7168553357 14337106714 21505660071 43011320142