Base | Representation |
---|---|
bin | 101000000011101011… |
… | …001010100101001110 |
3 | 11010000112101110011010 |
4 | 220003223022211032 |
5 | 1201041344221032 |
6 | 31431545510050 |
7 | 3051601121550 |
oct | 500353124516 |
9 | 133015343133 |
10 | 43011320142 |
11 | 1727185047a |
12 | 84044a2326 |
13 | 4095bcb4bb |
14 | 21204bd4d0 |
15 | 11bb064ccc |
hex | a03aca94e |
43011320142 has 16 divisors (see below), whose sum is σ = 98311588992. Its totient is φ = 12288948600.
The previous prime is 43011320141. The next prime is 43011320147. The reversal of 43011320142 is 24102311034.
It is a super-2 number, since 2×430113201422 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43011320141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 512039484 + ... + 512039567.
It is an arithmetic number, because the mean of its divisors is an integer number (6144474312).
Almost surely, 243011320142 is an apocalyptic number.
43011320142 is a gapful number since it is divisible by the number (42) formed by its first and last digit.
43011320142 is an abundant number, since it is smaller than the sum of its proper divisors (55300268850).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43011320142 is a wasteful number, since it uses less digits than its factorization.
43011320142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1024079063.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 43011320142 its reverse (24102311034), we get a palindrome (67113631176).
The spelling of 43011320142 in words is "forty-three billion, eleven million, three hundred twenty thousand, one hundred forty-two".
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