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430121051 is a prime number
BaseRepresentation
bin11001101000110…
…010000001011011
31002222100102011022
4121220302001123
51340102333201
6110402553055
713441653143
oct3150620133
91088312138
10430121051
11200879348
1210006878b
136b1596c9
14411a5923
1527b6341b
hex19a3205b

430121051 has 2 divisors, whose sum is σ = 430121052. Its totient is φ = 430121050.

The previous prime is 430120997. The next prime is 430121089. The reversal of 430121051 is 150121034.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 430121051 - 26 = 430120987 is a prime.

It is not a weakly prime, because it can be changed into another prime (430121651) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215060525 + 215060526.

It is an arithmetic number, because the mean of its divisors is an integer number (215060526).

Almost surely, 2430121051 is an apocalyptic number.

430121051 is a deficient number, since it is larger than the sum of its proper divisors (1).

430121051 is an equidigital number, since it uses as much as digits as its factorization.

430121051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 430121051 is about 20739.3599467293. The cubic root of 430121051 is about 754.8550522145.

Subtracting from 430121051 its sum of digits (17), we obtain a palindrome (430121034).

Adding to 430121051 its reverse (150121034), we get a palindrome (580242085).

It can be divided in two parts, 4301 and 21051, that added together give a palindrome (25352).

The spelling of 430121051 in words is "four hundred thirty million, one hundred twenty-one thousand, fifty-one".