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43014221113 is a prime number
BaseRepresentation
bin101000000011110110…
…001110110100111001
311010000201211211112111
4220003312032310321
51201043120033423
631432132012321
73051634563313
oct500366166471
9133021754474
1043014221113
1117273451a76
1284054610a1
1340966a5a56
142120a367b3
1511bb43960d
hexa03d8ed39

43014221113 has 2 divisors, whose sum is σ = 43014221114. Its totient is φ = 43014221112.

The previous prime is 43014221059. The next prime is 43014221161. The reversal of 43014221113 is 31112241034.

43014221113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22355333289 + 20658887824 = 149517^2 + 143732^2 .

It is a cyclic number.

It is not a de Polignac number, because 43014221113 - 213 = 43014212921 is a prime.

It is not a weakly prime, because it can be changed into another prime (43014221513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21507110556 + 21507110557.

It is an arithmetic number, because the mean of its divisors is an integer number (21507110557).

Almost surely, 243014221113 is an apocalyptic number.

It is an amenable number.

43014221113 is a deficient number, since it is larger than the sum of its proper divisors (1).

43014221113 is an equidigital number, since it uses as much as digits as its factorization.

43014221113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 43014221113 its reverse (31112241034), we get a palindrome (74126462147).

The spelling of 43014221113 in words is "forty-three billion, fourteen million, two hundred twenty-one thousand, one hundred thirteen".