Base | Representation |
---|---|
bin | 10011100100000101110110… |
… | …01000111111111011000111 |
3 | 12122022211002112201002021012 |
4 | 21302002323020333323013 |
5 | 21114331044211310421 |
6 | 231255452524112435 |
7 | 12030126446322665 |
oct | 1162027310777307 |
9 | 178284075632235 |
10 | 43021532135111 |
11 | 12787369359632 |
12 | 49a9a4009571b |
13 | 1b00bb40362ca |
14 | a8a378d63c35 |
15 | 4e914e97295b |
hex | 2720bb23fec7 |
43021532135111 has 4 divisors (see below), whose sum is σ = 43032317181000. Its totient is φ = 43010747089224.
The previous prime is 43021532135089. The next prime is 43021532135123. The reversal of 43021532135111 is 11153123512034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-43021532135111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43021532435111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5392516961 + ... + 5392524938.
It is an arithmetic number, because the mean of its divisors is an integer number (10758079295250).
Almost surely, 243021532135111 is an apocalyptic number.
43021532135111 is a deficient number, since it is larger than the sum of its proper divisors (10785045889).
43021532135111 is a wasteful number, since it uses less digits than its factorization.
43021532135111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10785045888.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 43021532135111 its reverse (11153123512034), we get a palindrome (54174655647145).
The spelling of 43021532135111 in words is "forty-three trillion, twenty-one billion, five hundred thirty-two million, one hundred thirty-five thousand, one hundred eleven".
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