430231211341133 has 4 divisors (see below), whose sum is σ = 430244667452028. Its totient is φ = 430217755230240.

The previous prime is 430231211341121. The next prime is 430231211341147. The reversal of 430231211341133 is 331143112132034.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 271155601040809 + 159075610300324 = 16466803^2 + 12612518^2 .

It is a cyclic number.

It is not a de Polignac number, because 430231211341133 - 2¹⁰ = 430231211340109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 430231211341133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (430231211341733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6728007488 + ... + 6728071433.

It is an arithmetic number, because the mean of its divisors is an integer number (107561166863007).

Almost surely, 2^{430231211341133} is an apocalyptic number.

It is an amenable number.

430231211341133 is a deficient number, since it is larger than the sum of its proper divisors (13456110895).

430231211341133 is a wasteful number, since it uses less digits than its factorization.

430231211341133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13456110894.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 430231211341133 its reverse (331143112132034), we get a palindrome (761374323473167).

The spelling of 430231211341133 in words is "four hundred thirty trillion, two hundred thirty-one billion, two hundred eleven million, three hundred forty-one thousand, one hundred thirty-three".