43031213431 has 4 divisors (see below), whose sum is σ = 44080755264. Its totient is φ = 41981671600.

The previous prime is 43031213419. The next prime is 43031213437. The reversal of 43031213431 is 13431213034.

43031213431 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43031213431 - 2⁹ = 43031212919 is a prime.

It is a super-2 number, since 2×43031213431² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 43031213396 and 43031213405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43031213437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 524770855 + ... + 524770936.

It is an arithmetic number, because the mean of its divisors is an integer number (11020188816).

Almost surely, 2^43031213431 is an apocalyptic number.

43031213431 is a gapful number since it is divisible by the number (41) formed by its first and last digit.

43031213431 is a deficient number, since it is larger than the sum of its proper divisors (1049541833).

43031213431 is a wasteful number, since it uses less digits than its factorization.

43031213431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1049541832.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 43031213431 its reverse (13431213034), we get a palindrome (56462426465).

The spelling of 43031213431 in words is "forty-three billion, thirty-one million, two hundred thirteen thousand, four hundred thirty-one".