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43034450143 = 131328507253
BaseRepresentation
bin101000000101000011…
…011001100011011111
311010002010220120112211
4220011003121203133
51201113304401033
631434133341251
73052301535136
oct500503314337
9133063816484
1043034450143
1117283909383
128410197827
13409a9394a9
1421235c091d
1511bd0d32cd
hexa050d98df

43034450143 has 4 divisors (see below), whose sum is σ = 43362957528. Its totient is φ = 42705942760.

The previous prime is 43034450141. The next prime is 43034450149. The reversal of 43034450143 is 34105443034.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 43034450143 - 21 = 43034450141 is a prime.

It is a super-2 number, since 2×430344501432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (43034450141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164253496 + ... + 164253757.

It is an arithmetic number, because the mean of its divisors is an integer number (10840739382).

Almost surely, 243034450143 is an apocalyptic number.

43034450143 is a deficient number, since it is larger than the sum of its proper divisors (328507385).

43034450143 is a wasteful number, since it uses less digits than its factorization.

43034450143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 328507384.

The product of its (nonzero) digits is 34560, while the sum is 31.

Adding to 43034450143 its reverse (34105443034), we get a palindrome (77139893177).

The spelling of 43034450143 in words is "forty-three billion, thirty-four million, four hundred fifty thousand, one hundred forty-three".

Divisors: 1 131 328507253 43034450143