430400011 has 2 divisors, whose sum is σ = 430400012. Its totient is φ = 430400010.

The previous prime is 430399997. The next prime is 430400057. The reversal of 430400011 is 110004034.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 430400011 - 2⁷ = 430399883 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 430399964 and 430400000.

It is not a weakly prime, because it can be changed into another prime (430500011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215200005 + 215200006.

It is an arithmetic number, because the mean of its divisors is an integer number (215200006).

Almost surely, 2^430400011 is an apocalyptic number.

430400011 is a deficient number, since it is larger than the sum of its proper divisors (1).

430400011 is an equidigital number, since it uses as much as digits as its factorization.

430400011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 430400011 is about 20746.0842329342. The cubic root of 430400011 is about 755.0182069495.

Adding to 430400011 its reverse (110004034), we get a palindrome (540404045).

The spelling of 430400011 in words is "four hundred thirty million, four hundred thousand, eleven".