4304025121213 has 4 divisors (see below), whose sum is σ = 4395600123840. Its totient is φ = 4212450118588.

The previous prime is 4304025121181. The next prime is 4304025121217. The reversal of 4304025121213 is 3121215204034.

4304025121213 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4304025121213 - 2⁵ = 4304025121181 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4304025121217) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45787501243 + ... + 45787501336.

It is an arithmetic number, because the mean of its divisors is an integer number (1098900030960).

Almost surely, 2^{4304025121213} is an apocalyptic number.

It is an amenable number.

4304025121213 is a deficient number, since it is larger than the sum of its proper divisors (91575002627).

4304025121213 is an equidigital number, since it uses as much as digits as its factorization.

4304025121213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91575002626.

The product of its (nonzero) digits is 5760, while the sum is 28.

The spelling of 4304025121213 in words is "four trillion, three hundred four billion, twenty-five million, one hundred twenty-one thousand, two hundred thirteen".