Base | Representation |
---|---|
bin | 10011100100101001000001… |
… | …00110001000111100000011 |
3 | 12122101121211110112102120111 |
4 | 21302110200212020330003 |
5 | 21120133232010022321 |
6 | 231312254315052151 |
7 | 12031365404614243 |
oct | 1162244046107403 |
9 | 178347743472514 |
10 | 43040414142211 |
11 | 127943787a3a82 |
12 | 49b162b741057 |
13 | 1b02902c00585 |
14 | a8b24a985b23 |
15 | 4e98a74a15e1 |
hex | 272520988f03 |
43040414142211 has 2 divisors, whose sum is σ = 43040414142212. Its totient is φ = 43040414142210.
The previous prime is 43040414142199. The next prime is 43040414142217. The reversal of 43040414142211 is 11224141404034.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43040414142211 - 217 = 43040414011139 is a prime.
It is not a weakly prime, because it can be changed into another prime (43040414142217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21520207071105 + 21520207071106.
It is an arithmetic number, because the mean of its divisors is an integer number (21520207071106).
Almost surely, 243040414142211 is an apocalyptic number.
43040414142211 is a deficient number, since it is larger than the sum of its proper divisors (1).
43040414142211 is an equidigital number, since it uses as much as digits as its factorization.
43040414142211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 43040414142211 its reverse (11224141404034), we get a palindrome (54264555546245).
The spelling of 43040414142211 in words is "forty-three trillion, forty billion, four hundred fourteen million, one hundred forty-two thousand, two hundred eleven".
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