Base | Representation |
---|---|
bin | 1100100001101110000… |
… | …10001010100101001111 |
3 | 1112010222201020201120020 |
4 | 12100313002022211033 |
5 | 24023000012402421 |
6 | 525422055153223 |
7 | 43045132003161 |
oct | 6206702124517 |
9 | 1463881221506 |
10 | 430420044111 |
11 | 1565a3991822 |
12 | 6b502975813 |
13 | 31785a42245 |
14 | 16b9230c931 |
15 | b2e2344dc6 |
hex | 643708a94f |
430420044111 has 4 divisors (see below), whose sum is σ = 573893392152. Its totient is φ = 286946696072.
The previous prime is 430420044073. The next prime is 430420044133. The reversal of 430420044111 is 111440024034.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 430420044111 - 217 = 430419913039 is a prime.
It is a super-2 number, since 2×4304200441112 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (430420044311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71736674016 + ... + 71736674021.
It is an arithmetic number, because the mean of its divisors is an integer number (143473348038).
Almost surely, 2430420044111 is an apocalyptic number.
430420044111 is a deficient number, since it is larger than the sum of its proper divisors (143473348041).
430420044111 is a wasteful number, since it uses less digits than its factorization.
430420044111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 143473348040.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 430420044111 its reverse (111440024034), we get a palindrome (541860068145).
The spelling of 430420044111 in words is "four hundred thirty billion, four hundred twenty million, forty-four thousand, one hundred eleven".
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