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4304214113 is a prime number
BaseRepresentation
bin1000000001000110…
…10001100001100001
3102002222010201202112
410000203101201201
532303334322423
61551034125105
7211443134123
oct40043214141
912088121675
104304214113
111909686851
12a01580795
13537966674
142cb903213
151a2d17a78
hex1008d1861

4304214113 has 2 divisors, whose sum is σ = 4304214114. Its totient is φ = 4304214112.

The previous prime is 4304214097. The next prime is 4304214121. The reversal of 4304214113 is 3114124034.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3831238609 + 472975504 = 61897^2 + 21748^2 .

It is a cyclic number.

It is not a de Polignac number, because 4304214113 - 24 = 4304214097 is a prime.

It is not a weakly prime, because it can be changed into another prime (4304214143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2152107056 + 2152107057.

It is an arithmetic number, because the mean of its divisors is an integer number (2152107057).

Almost surely, 24304214113 is an apocalyptic number.

It is an amenable number.

4304214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4304214113 is an equidigital number, since it uses as much as digits as its factorization.

4304214113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 23.

The square root of 4304214113 is about 65606.5096846342. The cubic root of 4304214113 is about 1626.6643760372.

Adding to 4304214113 its reverse (3114124034), we get a palindrome (7418338147).

The spelling of 4304214113 in words is "four billion, three hundred four million, two hundred fourteen thousand, one hundred thirteen".