Base | Representation |
---|---|
bin | 111110101000101110101… |
… | …110010110010010000101 |
3 | 120020111020221020002211112 |
4 | 332220232232112102011 |
5 | 1031010242312214141 |
6 | 13053215332414405 |
7 | 622656404644301 |
oct | 76505656262205 |
9 | 16214227202745 |
10 | 4304341132421 |
11 | 140a50839aa10 |
12 | 596263177405 |
13 | 252b89118945 |
14 | 10c48cc34d01 |
15 | 76e748257eb |
hex | 3ea2eb96485 |
4304341132421 has 16 divisors (see below), whose sum is σ = 4899986898048. Its totient is φ = 3742765118400.
The previous prime is 4304341132391. The next prime is 4304341132423. The reversal of 4304341132421 is 1242311434034.
4304341132421 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-4304341132421 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4304341132423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6758291 + ... + 7367711.
It is an arithmetic number, because the mean of its divisors is an integer number (306249181128).
Almost surely, 24304341132421 is an apocalyptic number.
It is an amenable number.
4304341132421 is a deficient number, since it is larger than the sum of its proper divisors (595645765627).
4304341132421 is a wasteful number, since it uses less digits than its factorization.
4304341132421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 637372.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 4304341132421 its reverse (1242311434034), we get a palindrome (5546652566455).
The spelling of 4304341132421 in words is "four trillion, three hundred four billion, three hundred forty-one million, one hundred thirty-two thousand, four hundred twenty-one".
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