Base | Representation |
---|---|
bin | 111110101000110010010… |
… | …011100010001011000111 |
3 | 120020111102010021110122221 |
4 | 332220302103202023013 |
5 | 1031010403202241403 |
6 | 13053225320233211 |
7 | 622661034422566 |
oct | 76506223421307 |
9 | 16214363243587 |
10 | 4304401212103 |
11 | 140a5392a5743 |
12 | 59627b30b807 |
13 | 252b986c2c55 |
14 | 10c496bd3bdd |
15 | 76e79c41dbd |
hex | 3ea324e22c7 |
4304401212103 has 4 divisors (see below), whose sum is σ = 4304466792808. Its totient is φ = 4304335631400.
The previous prime is 4304401212071. The next prime is 4304401212109. The reversal of 4304401212103 is 3012121044034.
4304401212103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4304401212103 - 25 = 4304401212071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4304401212109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32691801 + ... + 32823202.
It is an arithmetic number, because the mean of its divisors is an integer number (1076116698202).
Almost surely, 24304401212103 is an apocalyptic number.
4304401212103 is a deficient number, since it is larger than the sum of its proper divisors (65580705).
4304401212103 is an equidigital number, since it uses as much as digits as its factorization.
4304401212103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65580704.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4304401212103 its reverse (3012121044034), we get a palindrome (7316522256137).
The spelling of 4304401212103 in words is "four trillion, three hundred four billion, four hundred one million, two hundred twelve thousand, one hundred three".
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