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43044250153 is a prime number
BaseRepresentation
bin101000000101101000…
…110010001000101001
311010002211100110122011
4220011220302020221
51201123312001103
631435123355521
73052451042452
oct500550621051
9133084313564
1043044250153
11172893a2263
128413522ba1
13409c98b008
142124a12129
1511bddbbd6d
hexa05a32229

43044250153 has 2 divisors, whose sum is σ = 43044250154. Its totient is φ = 43044250152.

The previous prime is 43044250141. The next prime is 43044250211. The reversal of 43044250153 is 35105244034.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 26908137369 + 16136112784 = 164037^2 + 127028^2 .

It is a cyclic number.

It is not a de Polignac number, because 43044250153 - 29 = 43044249641 is a prime.

It is not a weakly prime, because it can be changed into another prime (43044250133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21522125076 + 21522125077.

It is an arithmetic number, because the mean of its divisors is an integer number (21522125077).

Almost surely, 243044250153 is an apocalyptic number.

It is an amenable number.

43044250153 is a deficient number, since it is larger than the sum of its proper divisors (1).

43044250153 is an equidigital number, since it uses as much as digits as its factorization.

43044250153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 43044250153 its reverse (35105244034), we get a palindrome (78149494187).

The spelling of 43044250153 in words is "forty-three billion, forty-four million, two hundred fifty thousand, one hundred fifty-three".