Base | Representation |
---|---|
bin | 10011100100110010001100… |
… | …01101101001111010010011 |
3 | 12122102002112202211101000112 |
4 | 21302121012031221322103 |
5 | 21120223324044201141 |
6 | 231314431210111535 |
7 | 12031631441622164 |
oct | 1162310615517223 |
9 | 178362482741015 |
10 | 43045340225171 |
11 | 12796476405019 |
12 | 49b258541b5ab |
13 | 1b0320964b76b |
14 | a8b596cc576b |
15 | 4e9a94ba67eb |
hex | 272646369e93 |
43045340225171 has 2 divisors, whose sum is σ = 43045340225172. Its totient is φ = 43045340225170.
The previous prime is 43045340225101. The next prime is 43045340225177. The reversal of 43045340225171 is 17152204354034.
43045340225171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43045340225171 - 210 = 43045340224147 is a prime.
It is not a weakly prime, because it can be changed into another prime (43045340225177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21522670112585 + 21522670112586.
It is an arithmetic number, because the mean of its divisors is an integer number (21522670112586).
Almost surely, 243045340225171 is an apocalyptic number.
43045340225171 is a deficient number, since it is larger than the sum of its proper divisors (1).
43045340225171 is an equidigital number, since it uses as much as digits as its factorization.
43045340225171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 403200, while the sum is 41.
The spelling of 43045340225171 in words is "forty-three trillion, forty-five billion, three hundred forty million, two hundred twenty-five thousand, one hundred seventy-one".
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