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430550152020019 is a prime number
BaseRepresentation
bin110000111100101010100010…
…0110111101000000000110011
32002110110012012101001011202101
41201321111010313220000303
5422413113202404120034
64123412002001201231
7156455136064336063
oct14171250467500063
92073405171034671
10430550152020019
1111520632643a079
1240357606930217
1315631922202c55
147846a4a7db3a3
1534b98e690d514
hex1879544de8033

430550152020019 has 2 divisors, whose sum is σ = 430550152020020. Its totient is φ = 430550152020018.

The previous prime is 430550152019983. The next prime is 430550152020077. The reversal of 430550152020019 is 910020251055034.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 430550152020019 - 213 = 430550152011827 is a prime.

It is a super-2 number, since 2×4305501520200192 (a number of 30 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 430550152020019.

It is not a weakly prime, because it can be changed into another prime (430550152020089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215275076010009 + 215275076010010.

It is an arithmetic number, because the mean of its divisors is an integer number (215275076010010).

Almost surely, 2430550152020019 is an apocalyptic number.

430550152020019 is a deficient number, since it is larger than the sum of its proper divisors (1).

430550152020019 is an equidigital number, since it uses as much as digits as its factorization.

430550152020019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 37.

The spelling of 430550152020019 in words is "four hundred thirty trillion, five hundred fifty billion, one hundred fifty-two million, twenty thousand, nineteen".