Base | Representation |
---|---|
bin | 10011100110011111011110… |
… | …10001011010001000000001 |
3 | 12122121200222122111022200010 |
4 | 21303033233101122020001 |
5 | 21122204003322232231 |
6 | 231401413115215133 |
7 | 12036106402252656 |
oct | 1163175721321001 |
9 | 178550878438603 |
10 | 43104011133441 |
11 | 12809343624865 |
12 | 4a01a1a1474a9 |
13 | 1b088c992622b |
14 | a90361043c2d |
15 | 4eb37a8be546 |
hex | 2733ef45a201 |
43104011133441 has 32 divisors (see below), whose sum is σ = 60943728067200. Its totient is φ = 27005217177600.
The previous prime is 43104011133371. The next prime is 43104011133487. The reversal of 43104011133441 is 14433111040134.
It is not a de Polignac number, because 43104011133441 - 215 = 43104011100673 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 43104011133399 and 43104011133408.
It is not an unprimeable number, because it can be changed into a prime (43104011134441) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 277652641 + ... + 277807841.
It is an arithmetic number, because the mean of its divisors is an integer number (1904491502100).
Almost surely, 243104011133441 is an apocalyptic number.
It is an amenable number.
43104011133441 is a deficient number, since it is larger than the sum of its proper divisors (17839716933759).
43104011133441 is a wasteful number, since it uses less digits than its factorization.
43104011133441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163329.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 43104011133441 its reverse (14433111040134), we get a palindrome (57537122173575).
The spelling of 43104011133441 in words is "forty-three trillion, one hundred four billion, eleven million, one hundred thirty-three thousand, four hundred forty-one".
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