Base | Representation |
---|---|
bin | 10011100110011111100001… |
… | …00110010110010011001101 |
3 | 12122121201001012101120122222 |
4 | 21303033300212112103031 |
5 | 21122204030022300023 |
6 | 231401415232345125 |
7 | 12036110062442045 |
oct | 1163176046262315 |
9 | 178551035346588 |
10 | 43104033400013 |
11 | 12809355152a93 |
12 | 4a01a256a51a5 |
13 | 1b08901421211 |
14 | a90363d9c725 |
15 | 4eb37c81bcc8 |
hex | 2733f09964cd |
43104033400013 has 4 divisors (see below), whose sum is σ = 44494486090368. Its totient is φ = 41713580709660.
The previous prime is 43104033400003. The next prime is 43104033400033. The reversal of 43104033400013 is 31000433040134.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 43104033400013 - 24 = 43104033399997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43104033400003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 695226345131 + ... + 695226345192.
It is an arithmetic number, because the mean of its divisors is an integer number (11123621522592).
Almost surely, 243104033400013 is an apocalyptic number.
It is an amenable number.
43104033400013 is a deficient number, since it is larger than the sum of its proper divisors (1390452690355).
43104033400013 is a wasteful number, since it uses less digits than its factorization.
43104033400013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1390452690354.
The product of its (nonzero) digits is 5184, while the sum is 26.
Adding to 43104033400013 its reverse (31000433040134), we get a palindrome (74104466440147).
The spelling of 43104033400013 in words is "forty-three trillion, one hundred four billion, thirty-three million, four hundred thousand, thirteen".
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