Base | Representation |
---|---|
bin | 10011100110100000010001… |
… | …11110111101001101110011 |
3 | 12122121202002201012012220101 |
4 | 21303100020332331031303 |
5 | 21122210344240112201 |
6 | 231401524005053231 |
7 | 12036123160662145 |
oct | 1163201076751563 |
9 | 178552081165811 |
10 | 43104442504051 |
11 | 128095450769a5 |
12 | 4a01b1a6b7217 |
13 | 1b089680cc606 |
14 | a903a2452c95 |
15 | 4eb3a36ccd01 |
hex | 273408fbd373 |
43104442504051 has 2 divisors, whose sum is σ = 43104442504052. Its totient is φ = 43104442504050.
The previous prime is 43104442504001. The next prime is 43104442504061. The reversal of 43104442504051 is 15040524440134.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 43104442504051 - 213 = 43104442495859 is a prime.
It is a super-3 number, since 3×431044425040513 (a number of 42 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 43104442504051.
It is not a weakly prime, because it can be changed into another prime (43104442504001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21552221252025 + 21552221252026.
It is an arithmetic number, because the mean of its divisors is an integer number (21552221252026).
Almost surely, 243104442504051 is an apocalyptic number.
43104442504051 is a deficient number, since it is larger than the sum of its proper divisors (1).
43104442504051 is an equidigital number, since it uses as much as digits as its factorization.
43104442504051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 153600, while the sum is 37.
Adding to 43104442504051 its reverse (15040524440134), we get a palindrome (58144966944185).
The spelling of 43104442504051 in words is "forty-three trillion, one hundred four billion, four hundred forty-two million, five hundred four thousand, fifty-one".
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