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431101444101137 is a prime number
BaseRepresentation
bin110001000000101011010000…
…0011100000001010000010001
32002112101220011212100120200222
41202001112200130001100101
5423001131224142214022
64124513134103522425
7156543023444610515
oct14201264034012021
92075356155316628
10431101444101137
111153a9106449257
1240426421459415
13156718cb9b5184
1478655c7bb0145
1534c8e10560242
hex18815a0701411

431101444101137 has 2 divisors, whose sum is σ = 431101444101138. Its totient is φ = 431101444101136.

The previous prime is 431101444101103. The next prime is 431101444101149. The reversal of 431101444101137 is 731101444101134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 414211678500481 + 16889765600656 = 20352191^2 + 4109716^2 .

It is a cyclic number.

It is not a de Polignac number, because 431101444101137 - 220 = 431101443052561 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 431101444101097 and 431101444101106.

It is not a weakly prime, because it can be changed into another prime (431101444101157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 215550722050568 + 215550722050569.

It is an arithmetic number, because the mean of its divisors is an integer number (215550722050569).

Almost surely, 2431101444101137 is an apocalyptic number.

It is an amenable number.

431101444101137 is a deficient number, since it is larger than the sum of its proper divisors (1).

431101444101137 is an equidigital number, since it uses as much as digits as its factorization.

431101444101137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 35.

The spelling of 431101444101137 in words is "four hundred thirty-one trillion, one hundred one billion, four hundred forty-four million, one hundred one thousand, one hundred thirty-seven".