| Base | Representation |
|---|---|
| bin | 101000001001101100… |
| … | …110101011100001111 |
| 3 | 11010021120121220122100 |
| 4 | 220021230311130033 |
| 5 | 1201243234434020 |
| 6 | 31450000450143 |
| 7 | 3054236350620 |
| oct | 501154653417 |
| 9 | 133246556570 |
| 10 | 43112421135 |
| 11 | 17313924113 |
| 12 | 8432319953 |
| 13 | 40b0b39184 |
| 14 | 212dab9a47 |
| 15 | 11c4d85a90 |
| hex | a09b3570f |
43112421135 has 72 divisors (see below), whose sum is σ = 87437155104. Its totient is φ = 19249937280.
The previous prime is 43112421133. The next prime is 43112421151. The reversal of 43112421135 is 53112421134.
43112421135 is a `hidden beast` number, since 431 + 12 + 4 + 211 + 3 + 5 = 666.
43112421135 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 43112421135 - 21 = 43112421133 is a prime.
It is a super-2 number, since 2×431124211352 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 43112421099 and 43112421108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (43112421133) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 545425 + ... + 619445.
It is an arithmetic number, because the mean of its divisors is an integer number (1214404932).
Almost surely, 243112421135 is an apocalyptic number.
43112421135 is a gapful number since it is divisible by the number (45) formed by its first and last digit.
43112421135 is an abundant number, since it is smaller than the sum of its proper divisors (44324733969).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
43112421135 is a wasteful number, since it uses less digits than its factorization.
43112421135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74125 (or 74079 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
Adding to 43112421135 its reverse (53112421134), we get a palindrome (96224842269).
Subtracting 43112421135 from its reverse (53112421134), we obtain a palindrome (9999999999).
The spelling of 43112421135 in words is "forty-three billion, one hundred twelve million, four hundred twenty-one thousand, one hundred thirty-five".
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