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43113121 is a prime number
BaseRepresentation
bin1010010001110…
…1101010100001
310000010101002021
42210131222201
542014104441
64140021441
71032312142
oct244355241
9100111067
1043113121
1122377587
1212531881
138c1682c
145a23ac9
153bb93d1
hex291daa1

43113121 has 2 divisors, whose sum is σ = 43113122. Its totient is φ = 43113120.

The previous prime is 43113107. The next prime is 43113131. The reversal of 43113121 is 12131134.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32615521 + 10497600 = 5711^2 + 3240^2 .

It is a cyclic number.

It is not a de Polignac number, because 43113121 - 29 = 43112609 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 43113095 and 43113104.

It is not a weakly prime, because it can be changed into another prime (43113131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21556560 + 21556561.

It is an arithmetic number, because the mean of its divisors is an integer number (21556561).

Almost surely, 243113121 is an apocalyptic number.

It is an amenable number.

43113121 is a deficient number, since it is larger than the sum of its proper divisors (1).

43113121 is an equidigital number, since it uses as much as digits as its factorization.

43113121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 16.

The square root of 43113121 is about 6566.0582543867. The cubic root of 43113121 is about 350.6467524525.

Adding to 43113121 its reverse (12131134), we get a palindrome (55244255).

It can be divided in two parts, 43113 and 121, that added together give a palindrome (43234).

The spelling of 43113121 in words is "forty-three million, one hundred thirteen thousand, one hundred twenty-one".